The first common task you will need to master is to substitute given values for specific variables. This is the task of turning an unknown letter into a known number. To do so, replace the letter variable by empty parentheses ( ) to preserve the place of the variable. Then drop the known value into the parentheses. Follow the usual Arithmetic rules (order of operations) to simplify.
Whenever you see a statement like "x = a number," you are being told exactly what x is. Knowing the value for x, you are free to replace the x in that expression by its actual value, for they are the same.
Example 1 Evaluate 3x - 4 when x = 5.
Solution: 3x - 4 means 3 times a number, then subtract 4.
| Write: | 3( ) - 4 | (The empty parentheses hold the space of the x) |
| = 3(5) - 4 | (Fill the parentheses with the given value of x) | |
| = 15 - 4 | (Simplify according to the Order of Operations) | |
| = 11 |
Example 2 Evaluate 2ab - 5b when a = -2 and b = 3.
Solution: Write 2( )( ) - 5( ) where the parentheses save spaces for a and b.
= -12 - 15 (Do the multiplications, then add)
= -27
If x = -2, y = 4, and a = 1, evaluate each of the following:
| 1) 4x - 3 | 2) y - x | 3) axy |
| 4) 3x | 5) a + y | 6) x - 2a + y |
| 7) 2a - 5x + y | 8) a - xy | 9) 3 - 2x |
| 10) a + 5 | 11) a + b - c | 12) 4a - 2bc |
| 13) c - 3a | 14) c - b | 15) (3c + a)/b |
| 16) c(3a - 2b) | 17) c - 4(b + 2) | 18) (a - 3) (2c + 1) |
The most important idea for working with variable expressions is to work only with the separate terms. A term will consist of a signed number multiplied by one or more variables. In a variable expression, you may have several terms. Each + or - sign will signal the start of a new term. For example, the variable expression 5x - 3y + 4ab consists of exactly three terms: +5x and -3y and +4ab. Terms may be moved within a variable expression, but be sure to carry the sign with each term. 5x + 4ab - 3y is the same expression, as is -3y + 4ab + 5x.
For now, you will need to be able to simplify additions and subtractions and a few simple multiplications. There is just one simple rule: Add or subtract like terms only. Like terms must have the same variable part.
Example 3 Simplify 3x + 7 + 2x - 3.
Solution: The terms can be reordered to group the x-terms and constant terms (terms with no variable).
| 3x + 7 + 2x - 3 | (Arrange the 3x and 2x terms together. Put the |
| = 3x + 2x + 7 - 3 | +7 and -3 together) |
| = 5x + 4 | (Add 3x and 2x to get 5x; Subtract +7 - 3 to get +4) |
| Solution: | 5x + 1 - 6x - 4 |
| = 5x - 6x + 1 - 4 | |
| = -1x + -3 | |
| = -x - 3 |
Example 5 Simplify 2(5x - 8).
| Solution: | 2(5x - 8) | |
| = 2(5x) - 2(8) | 2 times the group means 2 times each term. | |
| = 10x - 16 |
| Solution: | -3(y - 4) | |
| = -3(y) - 3(-4) | Multiply each term by -3. | |
| = -3y + 12 | Note that - times - is +. |
More Exercises
Simplify (add like terms only):
| 19) 4x + 3x | 20) 2x - 7x | 21) 10y + 2y - 5y |
| 22) 4x - 2 - 3x | 23) 6c - 8 + c + 3 | 24) -x - 2y + 3x |
| 25) 5x + 7 - 4x - 10 | 26) a - 3b + 10a + 5b - 2 | 27) 2x - 4y - 2x + 7y |
| 28) 2(3x + 1) | 29) 3(5x - 8) | 30) 7(2y - 3) |
| 31) 4(8a + 3) | 32) -2(3c + 2) | 33) -5(2x + 4) |
| 34) 2(9x - 4) | 35) -(x + 3) | 36) -(2y - 3) |
| 37) 5(3x + 2y - 5) | 38) -3(2x - 5y + 6) | 39) -(10 - 5x) |
| 40) 2x + 3(4x - 3) | 41) 9y + 2(3y + 1) | 42) 4 + 3(5x - 4) |
| 43) 3a - 2(5a + 1) | 44) 6 - (x - 5) | 45) 2(3x - 2) + 4 |
| 46) 4y - 3 when y = x + 2 | 47) 2z + 6 when z = 3x + 1 |
| 48) 1 - 2a when a = 4b + 3 | 49) 3 - y when y = 2x - 9 |
Formula Problems
Sometimes a word problem comes with a formula. Such problems appear at all levels of mathematics learning, from beginning algebra to calculus, and beyond. When given a formula, it is important to come to an understanding of what kind of number each letter in the formula represents. If you can match every number given in the word problem with a letter in the formula, you will be able to solve the problem.
Use the following steps to approach a formula problem.
2. Match each number in the problem statement with one of the letters in your list. Fill these values into the corresponding spaces in the formula.
3. Perform the indicated arithmetic operations to find the answer to the problem.
Solution: Use
So
Example 8 The amount of simple interest paid on a savings account is I = Prt, where P is the amount of the deposit, r is the interest rate, and t is the time (in years) that the deposit is kept in the account. How much interest is paid on a $4000 deposit left for 5 years in an account earning 6% simple interest?
Solution: Use the formula I = Prt.
| The known quantities are: | P = deposit = $4000 |
| r = rate = 6% = 0.06 | |
| t = time = 5 years |
More Exercises
Choose a formula from the list of frequently used formulas and use it to solve the problem.
50. What is the sale price of a pair of $55 boots marked 30% off?
51. How much interest is paid on an account earning 4% simple interest if $1200 is left on deposit for 8 years?
52. How far does a car travel in 3 and a half hours at 45 miles per hour?
53. If the temperature is 59° F, what is the Celsius temperature?
54. Find the area and the perimeter of a rectangle that is 14 centimeters long by 17 centimeters wide.
55. Find the area of a triangle with a base of 42 feet and a height of 15 feet.
56. An object is thrown straight up from a height of 4 feet above the ground at 75 feet per second. Find its height after 2 seconds.
este primer tema me pareció fácil e interesante!
ResponderEliminar-Rocio
Daniella R. Tosado García:
ResponderEliminarExcelente, pero tienes que estar pendiente de las reglas de los enteros.
Tienes que aprenderte el orden de operaciones.
ResponderEliminarSra. García,
ResponderEliminarEsta página es buena para estudiar.
Excelente idea para nuestro beneficio. Gracias.
ResponderEliminarZaymara Vivaldi
ResponderEliminarEsta pagina es muy interesante para nosotros poder aprender y estudiar.
Esta pagina me a ayudado en este tema, por los ejercicios adicionales que trajo.
ResponderEliminarBuena practica.
ResponderEliminar